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Reviewed CSCA Chemistry question · Standard

A colorless solution contains a mixture of chloride (Cl-) and nitrate (NO3-) ions. Which sequence of reagents will allow the chloride ion to be tested without interference from the nitrate ion?

  1. Add dilute nitric acid, then silver nitrate solution
  2. Add dilute hydrochloric acid, then barium chloride solution
  3. Add sodium hydroxide solution, then warm gently
  4. Add dilute sulfuric acid, then copper turnings
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Correct answer

A. Add dilute nitric acid, then silver nitrate solution

Principle or equation

Chloride ions are confirmed by adding silver nitrate solution to produce a white precipitate of silver chloride, which is soluble in dilute ammonia. Nitrate ions do not interfere because silver nitrate is soluble; nitric acid is added to remove carbonate or sulfite impurities and to provide acidic medium.

Why this answer is correct

To test for Cl-, add dilute nitric acid (to acidify and remove any carbonate or sulfite that might also precipitate with Ag+) and then silver nitrate solution. A white precipitate of AgCl forms, confirming chloride. Nitrate ions do not react with silver nitrate to form a precipitate, so they do not interfere. Option B would introduce chloride ions, interfering. Option C tests for ammonium ions, not chloride. Option D tests for nitrate ions, not chloride.

Example

Cl-(aq) + Ag+(aq) -> AgCl(s) (white precipitate). The precipitate dissolves in dilute ammonia, confirming chloride.

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