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Reviewed CSCA Chemistry question · Standard

A white powder is known to be either sodium oxide (Na2O) or sodium chloride (NaCl). Which test would best distinguish between them?

  1. Add water and test the pH of the resulting solution.
  2. Add dilute nitric acid and observe for effervescence.
  3. Heat the powder and observe for a flame color.
  4. Add silver nitrate solution and observe for a precipitate.
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Correct answer

A. Add water and test the pH of the resulting solution.

Principle or equation

Sodium oxide is a basic oxide that reacts with water to form sodium hydroxide, giving a strongly alkaline solution (pH > 7). Sodium chloride dissolves to give a neutral solution (pH ≈ 7).

Why this answer is correct

Step 1: Recognize that Na2O is a basic oxide. Step 2: When added to water, Na2O reacts: Na2O + H2O → 2NaOH, producing OH⁻ ions, so the solution is basic. Step 3: NaCl dissolves without hydrolysis, giving a neutral solution. Step 4: Testing pH distinguishes them. Adding dilute nitric acid: both dissolve, no effervescence for either (Na2O reacts but no gas). Flame color: both give yellow flame, not distinguishing. Silver nitrate: only NaCl gives white AgCl precipitate, but Na2O would also give Ag2O? Actually Ag2O is brown, but this test is less direct and not the best.

Example

If 0.5 g of the powder is added to 10 mL water, a pH paper shows pH 13 for Na2O and pH 7 for NaCl.

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