CSCAPrep
Reviewed CSCA Mathematics question · Hard

For the function f(x) = x^3 - 4x^2 + 5x - 2, what is the slope of the tangent line at x = 3?

  1. 8
  2. 4
  3. 14
  4. 2
Show the answer and explanation

Correct answer

A. 8

Principle or equation

The slope of the tangent line to f(x) at x = a is f'(a). Use the power rule: d/dx(x^n) = n x^(n-1).

Why this answer is correct

Compute f'(x) = 3x^2 - 8x + 5. Then f'(3) = 3(9) - 8(3) + 5 = 27 - 24 + 5 = 8.

Example

For f(x) = x^2 + 3x, f'(x) = 2x + 3, so at x = 1, slope = 5.

This published item includes a stored explanation and passed the platform’s publication workflow. It is independent preparation material, not a claim of an official or recalled examination question.

Related practice questions