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Reviewed CSCA Mathematics question · Standard

Consider the function f(x) = sqrt(16 - x^2) / (x^2 - 1). What is the domain of f?

  1. [-4, -1) ∪ (-1, 1) ∪ (1, 4]
  2. (-4, -1) ∪ (-1, 1) ∪ (1, 4)
  3. [-4, 4]
  4. (-∞, -1) ∪ (-1, 1) ∪ (1, ∞)
Show the answer and explanation

Correct answer

A. [-4, -1) ∪ (-1, 1) ∪ (1, 4]

Principle or equation

The domain consists of all real numbers x for which the expression is defined: the radicand must be nonnegative, and the denominator must not be zero.

Why this answer is correct

For sqrt(16 - x^2), require 16 - x^2 ≥ 0, so x ∈ [-4, 4]. Denominator x^2 - 1 ≠ 0, so x ≠ ±1. Intersecting gives [-4, -1) ∪ (-1, 1) ∪ (1, 4].

Example

For f(x) = sqrt(9 - x^2)/(x^2 - 4), domain is [-3, -2) ∪ (-2, 2) ∪ (2, 3].

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