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Reviewed CSCA Mathematics question · Easy

What is the range of the function f(x) = 2 + sqrt(x - 1)?

  1. [1, ∞)
  2. [2, ∞)
  3. (-∞, 2]
  4. [0, ∞)
Show the answer and explanation

Correct answer

B. [2, ∞)

Principle or equation

The square root function sqrt(x - 1) has range [0, ∞). Adding 2 shifts the range to [2, ∞).

Why this answer is correct

Since sqrt(x - 1) ≥ 0 for all x ≥ 1, f(x) = 2 + sqrt(x - 1) ≥ 2. As x increases, sqrt(x - 1) increases without bound, so the range is [2, ∞).

Example

For f(x) = 3 + sqrt(x), the range is [3, ∞).

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