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Reviewed CSCA Physics question · Easy

A particle moves in simple harmonic motion with an amplitude of 0.20 m and an angular frequency of 5.0 rad/s. What is the maximum speed of the particle?

  1. 0.040 m/s
  2. 1.0 m/s
  3. 0.20 m/s
  4. 25 m/s
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Correct answer

B. 1.0 m/s

Principle or equation

In simple harmonic motion, the maximum speed is v_max = A ω, where A is amplitude and ω is angular frequency.

Why this answer is correct

Substitute A = 0.20 m and ω = 5.0 rad/s: v_max = 0.20 × 5.0 = 1.0 m/s.

Example

If amplitude is 0.10 m and angular frequency is 10 rad/s, v_max = 0.10 × 10 = 1.0 m/s.

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