Reviewed CSCA Physics question · Easy

A 6 V battery is connected to two resistors in series: 2 Ω and 4 Ω. What is the current through the 4 Ω resistor?

0.5 A
1 A
1.5 A
3 A

Show the answer and explanation

Correct answer

B. 1 A

Principle or equation

Ohm's law: V = IR. In series, total resistance R_total = R1 + R2, and current is the same through all elements.

Why this answer is correct

R_total = 2 + 4 = 6 Ω. I = V / R_total = 6 V / 6 Ω = 1 A.

Example

If a 3 Ω and 6 Ω are in series with 9 V, I = 9/9 = 1 A.

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