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Reviewed CSCA Physics question · Easy

A 1 kg object is lifted vertically at constant speed from the ground to a height of 5 m. How much work is done against gravity? (Take g = 10 m/s^2)

  1. 5 J
  2. 10 J
  3. 50 J
  4. 500 J
Show the answer and explanation

Correct answer

C. 50 J

Principle or equation

Work done against gravity equals the change in gravitational potential energy: W = m g h.

Why this answer is correct

W = 1 * 10 * 5 = 50 J.

Example

Lifting a 2 kg object 3 m requires 2*10*3 = 60 J.

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