A 1 kg object is lifted vertically at constant speed from the ground to a height of 5 m. How much work is done against gravity? (Take g = 10 m/s^2)
Show the answer and explanation
Correct answer
C. 50 J
Principle or equation
Work done against gravity equals the change in gravitational potential energy: W = m g h.
Why this answer is correct
W = 1 * 10 * 5 = 50 J.
Example
Lifting a 2 kg object 3 m requires 2*10*3 = 60 J.
This published item includes a stored explanation and passed the platform’s publication workflow. It is independent preparation material, not a claim of an official or recalled examination question.