A car starts from rest and accelerates uniformly at 2 m/s^2 for 5 seconds. What is its displacement during this time?
Show the answer and explanation
Correct answer
B. 25 m
Principle or equation
For uniformly accelerated motion starting from rest, displacement s = (1/2) a t^2.
Why this answer is correct
Given a = 2 m/s^2, t = 5 s, and initial velocity u = 0. Using s = u t + (1/2) a t^2 = 0 + (1/2)(2)(5^2) = 25 m.
Example
A ball dropped from rest falls for 3 s. With g = 10 m/s^2, its fall distance is (1/2)(10)(3^2) = 45 m.
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