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Reviewed CSCA Physics question · Easy

A 5 kg object is lifted vertically at constant speed through a height of 2 m. How much work is done against gravity? (Take g = 10 m/s²)

  1. 10 J
  2. 50 J
  3. 100 J
  4. 200 J
Show the answer and explanation

Correct answer

C. 100 J

Principle or equation

Work done against gravity = mgh.

Why this answer is correct

W = 5 kg × 10 m/s² × 2 m = 100 J.

Example

Lifting a 2 kg mass 3 m requires 2×10×3 = 60 J.

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