A particle executes simple harmonic motion with an amplitude of 0.20 m and a frequency of 2.0 Hz. What is the maximum speed of the particle? (Use π ≈ 3.14)
Show the answer and explanation
Correct answer
A. 2.5 m/s
Principle or equation
In SHM, x(t) = A cos(ωt), so v_max = Aω, where ω = 2πf.
Why this answer is correct
ω = 2π × 2.0 = 4π ≈ 12.56 rad/s. v_max = Aω = 0.20 × 12.56 ≈ 2.51 m/s, which rounds to 2.5 m/s.
Example
If A = 0.1 m and f = 1 Hz, v_max = 0.1 × 2π ≈ 0.628 m/s.
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