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Reviewed CSCA Chemistry question · Easy

将 0.4 g 氢氧化钠固体溶于水配成 100 mL 溶液,该溶液的物质的量浓度是多少?(NaOH 摩尔质量为 40 g/mol)

  1. 0.01 mol/L
  2. 0.1 mol/L
  3. 0.4 mol/L
  4. 1.0 mol/L
Show the answer and explanation

Correct answer

B. 0.1 mol/L

Principle or equation

物质的量浓度 c = n / V,其中 n = m / M,V 为溶液体积(L)。

Why this answer is correct

n(NaOH) = 0.4 g / 40 g/mol = 0.01 mol,V = 100 mL = 0.100 L,c = 0.01 mol / 0.100 L = 0.1 mol/L。

Example

例如,将 1.6 g CuSO4(M=160 g/mol)配成 200 mL 溶液,n=0.01 mol,c=0.05 mol/L。

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