在温度为 27 ℃、压强为 1.0 × 10^5 Pa 的条件下，某气体的体积为 2.0 L。若温度升高到 127 ℃，压强保持不变，则该气体的体积变为多少？
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Correct answer
A. 2.7 L
Principle or equation
理想气体状态方程 pV = nRT，在压强和物质的量不变时，V 与热力学温度 T 成正比（查理定律的推论）。
Why this answer is correct
先换算热力学温度：T1 = 27 + 273 = 300 K，T2 = 127 + 273 = 400 K。压强不变时，V1/T1 = V2/T2，所以 V2 = V1 × T2/T1 = 2.0 L × 400/300 = 2.67 L，约 2.7 L。
Example
若 0 ℃ 时某气体体积为 1 L，压强不变，升温到 273 ℃，则体积为 2 L。
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