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Reviewed CSCA Physics question · Standard

A sealed container holds 2 moles of an ideal gas at a pressure of 1.0 × 10⁵ Pa and a temperature of 300 K. What is the volume of the container? (R = 8.31 J/(mol·K))

  1. 0.025 m³
  2. 0.050 m³
  3. 0.100 m³
  4. 0.200 m³
Show the answer and explanation

Correct answer

B. 0.050 m³

Principle or equation

Ideal gas law: PV = nRT.

Why this answer is correct

V = nRT / P = (2 mol * 8.31 J/(mol·K) * 300 K) / (1.0 × 10⁵ Pa) = (4986) / 100000 = 0.04986 m³ ≈ 0.050 m³.

Example

For 1 mole at 273 K and 1 atm (1.013×10⁵ Pa), V ≈ 0.0224 m³ (22.4 L).

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