An ideal gas occupies 2.0 L at a pressure of 1.0 atm and a temperature of 300 K. If the amount of gas is held constant, what will the volume be when the pressure is increased to 2.0 atm and the temperature is raised to 600 K?
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Correct answer
B. 2.0 L
Principle or equation
Ideal gas law: PV = nRT, so for constant n, P1 V1 / T1 = P2 V2 / T2.
Why this answer is correct
V2 = V1 * (P1/P2) * (T2/T1) = 2.0 * (1/2) * (600/300) = 2.0 * 0.5 * 2 = 2.0 L.
Example
If pressure doubles and temperature doubles, volume stays the same.
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