两个电阻 R1 = 6 Ω 和 R2 = 3 Ω 并联后,接到电压为12 V的电源两端。求通过 R2 的电流大小。
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Correct answer
C. 4 A
Principle or equation
并联电路各支路电压相等,等于电源电压。由欧姆定律 I = U/R 计算各支路电流。
Why this answer is correct
R2 两端电压为12 V,所以通过 R2 的电流 I2 = U/R2 = 12/3 = 4 A。
Example
若 R1=4 Ω,R2=6 Ω,电压为12 V,则通过 R2 的电流为2 A。
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