用频率为5.0×10¹⁴ Hz的光照射某金属表面，恰好发生光电效应。求该金属的逸出功（普朗克常量 h=6.63×10⁻³⁴ J·s）。
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Correct answer
A. 3.32×10⁻¹⁹ J
Principle or equation
光电效应方程：hν = W0 + Ek。恰好发生光电效应时 Ek=0，所以 W0 = hν。
Why this answer is correct
W0 = hν = 6.63×10⁻³⁴ × 5.0×10¹⁴ = 3.315×10⁻¹⁹ J ≈ 3.32×10⁻¹⁹ J。
Example
若频率为1.0×10¹⁵ Hz，则 W0 = 6.63×10⁻¹⁹ J。
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