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Reviewed CSCA Physics question · Easy

两个电阻R₁=6 Ω和R₂=3 Ω并联，接在电压为12 V的电源两端。求通过R₁的电流I₁和通过R₂的电流I₂。

  1. I₁=2 A，I₂=4 A
  2. I₁=4 A，I₂=2 A
  3. I₁=2 A，I₂=2 A
  4. I₁=1 A，I₂=2 A
Show the answer and explanation

Correct answer

A. I₁=2 A，I₂=4 A

Principle or equation

并联电路电压相等，欧姆定律：I = U/R。

Why this answer is correct

并联电压U=12 V。I₁ = U/R₁ = 12/6 = 2 A；I₂ = U/R₂ = 12/3 = 4 A。

Example

若R₁=4 Ω，R₂=2 Ω，U=8 V，则I₁=2 A，I₂=4 A。

This published item includes a stored explanation and passed the platform’s publication workflow. It is independent preparation material, not a claim of an official or recalled examination question.

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