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Reviewed CSCA STEM Chinese question · Standard

在实验室中,用分液漏斗进行萃取操作时,振荡后需要_,以排出产生的气体,防止漏斗内压强过大。

  1. 静置
  2. 放气
  3. 摇匀
  4. 加热
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Correct answer

B. 放气

Principle or equation

分液漏斗振荡后,内部可能产生气体,需打开活塞放气以平衡内外压强。

Why this answer is correct

萃取振荡后,应及时打开分液漏斗的活塞(或旋塞)进行放气,确保安全。

Example

用CCl₄萃取碘水中的碘,振荡后打开活塞放气,再关闭活塞静置分层。

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