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Reviewed CSCA Chemistry question · Easy

A 5.00 L flask contains 0.300 mol of an ideal gas at a pressure of 1.50 atm. What is the temperature of the gas in degrees Celsius? (R = 0.0821 L·atm·mol⁻¹·K⁻¹)

  1. 31.5 °C
  2. 58.0 °C
  3. 304.5 °C
  4. 577.5 °C
Show the answer and explanation

Correct answer

A. 31.5 °C

Principle or equation

The ideal gas equation is PV = nRT. Solve for T in kelvin, then convert to Celsius by subtracting 273.15.

Why this answer is correct

T = PV / (nR) = (1.50 atm * 5.00 L) / (0.300 mol * 0.0821 L·atm·mol⁻¹·K⁻¹) = 7.50 / 0.02463 = 304.5 K. Convert to Celsius: 304.5 - 273.15 = 31.35 °C, approximately 31.5 °C.

Example

For P = 1.50 atm, V = 5.00 L, n = 0.300 mol, T = 304.5 K = 31.5 °C.

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