What is the total number of oxygen atoms in 0.250 mol of potassium sulfate, K2SO4? (Avogadro constant = 6.02 × 10^23 mol^-1)
Show the answer and explanation
Correct answer
C. 6.02 × 10^23
Principle or equation
Each formula unit of K2SO4 contains 4 oxygen atoms. Number of O atoms = moles × 4 × Avogadro constant.
Why this answer is correct
0.250 mol × 4 = 1.00 mol O atoms. 1.00 mol × 6.02 × 10^23 = 6.02 × 10^23 atoms.
Example
For 0.100 mol Na2SO4, O atoms = 0.100 × 4 × 6.02e23 = 2.41e23.
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