A rigid container holds 0.300 mol of an ideal gas at a pressure of 1.20 atm and a temperature of 300 K. The gas is heated to 360 K while the volume remains constant. What is the new pressure in atm?
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Correct answer
A. 1.44
Principle or equation
For a fixed amount of gas at constant volume, pressure is directly proportional to absolute temperature (Gay-Lussac's law): P1/T1 = P2/T2.
Why this answer is correct
Given P1 = 1.20 atm, T1 = 300 K, T2 = 360 K. P2 = P1 × (T2/T1) = 1.20 × (360/300) = 1.20 × 1.20 = 1.44 atm.
Example
If a gas at 1.00 atm and 300 K is heated to 360 K at constant volume, the new pressure is 1.20 atm.
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