CSCAPrep
Reviewed CSCA Chemistry question · Easy

How many moles of oxygen atoms are present in 0.200 mol of zinc chlorate, Zn(ClO3)2?

  1. 0.200 mol
  2. 0.400 mol
  3. 1.20 mol
  4. 0.600 mol
Show the answer and explanation

Correct answer

C. 1.20 mol

Principle or equation

The formula unit Zn(ClO3)2 contains 2 chlorate ions, each with 3 oxygen atoms, so there are 6 oxygen atoms per formula unit. Moles of atoms = moles of compound × atoms per formula unit.

Why this answer is correct

In Zn(ClO3)2, there are 2 ClO3 groups, each contributing 3 O atoms, giving 6 O atoms per formula unit. Therefore, 0.200 mol × 6 = 1.20 mol of oxygen atoms.

Example

For 0.200 mol of Zn(ClO3)2, oxygen atoms = 0.200 × 6 = 1.20 mol.

This published item includes a stored explanation and passed the platform’s publication workflow. It is independent preparation material, not a claim of an official or recalled examination question.

Related practice questions