A 3.00 L flask contains 0.200 mol of an ideal gas at 27°C. What is the pressure in atm? (R = 0.0821 L·atm·mol⁻¹·K⁻¹)
Show the answer and explanation
Correct answer
A. 1.64 atm
Principle or equation
Ideal gas law: PV = nRT. Convert temperature to kelvin (K = °C + 273). Rearrange to P = nRT/V.
Why this answer is correct
T = 27 + 273 = 300 K. P = (0.200 mol)(0.0821 L·atm·mol⁻¹·K⁻¹)(300 K) / 3.00 L = 1.64 atm.
Example
P = (0.200 × 0.0821 × 300) / 3.00 = 1.64 atm.
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