What is the total number of nitrogen atoms in 0.150 mol of ammonium nitrate, NH4NO3? (Avogadro constant = 6.02 × 10^23 mol^-1)
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Correct answer
B. 1.81 × 10^23
Principle or equation
Each formula unit of NH4NO3 contains 2 nitrogen atoms. Number of atoms = moles × Avogadro constant × atoms per formula unit.
Why this answer is correct
NH4NO3 has two nitrogen atoms (one in NH4+, one in NO3-). Total N atoms = 0.150 mol × 6.02 × 10^23 mol^-1 × 2 = 1.806 × 10^23 ≈ 1.81 × 10^23.
Example
For 0.100 mol of NH4NO3, N atoms = 0.100 × 6.02 × 10^23 × 2 = 1.204 × 10^23.
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