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Reviewed CSCA Chemistry question · Standard

A student dissolves 0.040 mol of a strong monoprotic acid HA in enough water to make 800.0 mL of solution. What is the pH of the resulting solution? Assume complete dissociation.

  1. 1.30
  2. 1.00
  3. 0.70
  4. 2.00
Show the answer and explanation

Correct answer

A. 1.30

Principle or equation

For a strong monoprotic acid, complete dissociation means [H+] equals the acid concentration. pH = -log10[H+]. Concentration = moles / volume in liters.

Why this answer is correct

Moles of HA = 0.040 mol, volume = 800.0 mL = 0.800 L. [H+] = 0.040 / 0.800 = 0.050 M. pH = -log(0.050) = 1.30.

Example

For 0.020 mol in 0.400 L, [H+] = 0.050 M, pH = 1.30.

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