CSCAPrep
Reviewed CSCA Chemistry question · Hard

A rigid container holds 0.250 mol of an ideal gas at a pressure of 1.20 atm and a temperature of 300 K. The gas is heated to 360 K while the volume remains constant. What is the new pressure in atm?

  1. 1.44
  2. 1.00
  3. 1.20
  4. 1.80
Show the answer and explanation

Correct answer

A. 1.44

Principle or equation

At constant volume, pressure is directly proportional to absolute temperature: P1/T1 = P2/T2.

Why this answer is correct

P2 = P1 × (T2/T1) = 1.20 atm × (360 K / 300 K) = 1.44 atm.

Example

If P1 = 2.00 atm, T1 = 300 K, T2 = 450 K, then P2 = 3.00 atm.

This published item includes a stored explanation and passed the platform’s publication workflow. It is independent preparation material, not a claim of an official or recalled examination question.

Related practice questions