A rigid container holds 0.350 mol of an ideal gas at a pressure of 1.60 atm and a temperature of 310 K. The gas is heated to 390 K while the volume remains constant. What is the new pressure in atm?
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Correct answer
A. 2.01
Principle or equation
At constant volume, the pressure of an ideal gas is directly proportional to its absolute temperature: P1/T1 = P2/T2.
Why this answer is correct
Using P1/T1 = P2/T2, we have P2 = P1 × T2/T1 = 1.60 atm × (390 K / 310 K) = 1.60 × 1.2581 = 2.0129 atm, which rounds to 2.01 atm.
Example
If a gas at 300 K and 1.00 atm is heated to 360 K at constant volume, new pressure = 1.00 × 360/300 = 1.20 atm.
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