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Reviewed CSCA Chemistry question · Hard

A student prepares a solution by dissolving 0.0200 mol of a strong diprotic acid H2A in enough water to make 200.0 mL of solution. What is the pH of the resulting solution? Assume complete dissociation.

  1. 0.70
  2. 1.00
  3. 1.30
  4. 2.00
Show the answer and explanation

Correct answer

A. 0.70

Principle or equation

For a strong diprotic acid that dissociates completely, each mole of H2A produces 2 moles of H+. The concentration of H+ is twice the acid concentration. pH = -log10[H+].

Why this answer is correct

Moles of H+ = 0.0200 mol × 2 = 0.0400 mol. Volume = 200.0 mL = 0.200 L. [H+] = 0.0400 mol / 0.200 L = 0.200 M. pH = -log(0.200) = 0.699, which rounds to 0.70.

Example

For 0.0100 mol of H2SO4 in 100.0 mL, [H+] = 0.0200 mol / 0.100 L = 0.200 M, pH = 0.70.

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