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Reviewed CSCA Chemistry question · Standard

A student weighs out 17.4 g of manganese(IV) oxide, MnO2. How many moles of manganese atoms are present in this sample? (Molar masses: Mn = 54.9 g/mol, O = 16.0 g/mol)

  1. 0.100 mol
  2. 0.200 mol
  3. 0.317 mol
  4. 0.634 mol
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Correct answer

B. 0.200 mol

Principle or equation

The amount of substance in moles is calculated by dividing the mass by the molar mass. The molar mass of MnO2 is the sum of the molar masses of its constituent atoms: 54.9 g/mol + 2 × 16.0 g/mol = 86.9 g/mol. Since each formula unit contains one manganese atom, the moles of manganese atoms equal the moles of MnO2.

Why this answer is correct

Calculate the molar mass of MnO2: 54.9 + 2(16.0) = 86.9 g/mol. Then divide the given mass by the molar mass: 17.4 g ÷ 86.9 g/mol = 0.200 mol. Thus, the sample contains 0.200 mol of MnO2, which corresponds to 0.200 mol of Mn atoms.

Example

For a 43.45 g sample of MnO2, the amount is 43.45 g ÷ 86.9 g/mol = 0.500 mol, so it contains 0.500 mol of Mn atoms.

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