在恒温恒容密闭容器中，发生反应：A(g) + 2B(g) ⇌ 2C(g)。起始时充入1 mol A和2 mol B，达到平衡时测得C的物质的量为1.2 mol。则A的转化率为多少？
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Correct answer
C. 60%
Principle or equation
根据化学方程式计算转化量：生成1.2 mol C，消耗A的物质的量为1.2/2 = 0.6 mol。转化率 = 消耗量/起始量 × 100%。
Why this answer is correct
设A的转化量为x，则生成C为2x。由题意2x = 1.2，解得x = 0.6 mol。A的转化率 = 0.6/1 × 100% = 60%。
Example
若反应为N2 + 3H2 ⇌ 2NH3，生成0.8 mol NH3，则消耗N2 0.4 mol，转化率 = 0.4/起始N2×100%。
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