在恒温恒容密闭容器中,发生反应:2A(g) + B(g) ⇌ 2C(g)。起始时充入2 mol A和1 mol B,达到平衡时测得C的物质的量为1.2 mol。则B的转化率为多少?
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Correct answer
B. 60%
Principle or equation
根据化学方程式计量关系,由C的生成量计算消耗的B,转化率=消耗量/起始量×100%。
Why this answer is correct
生成1.2 mol C,消耗B的物质的量为1.2 mol÷2=0.6 mol。B的转化率=0.6 mol/1 mol×100%=60%。
Example
若反应为A+2B⇌2C,生成2mol C则消耗B 2mol。
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