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Reviewed CSCA Chemistry question · Standard

What is the pH of a solution prepared by dissolving 0.40 g of NaOH (molar mass 40 g/mol) in water to make 250 mL of solution? Assume complete dissociation.

  1. 1.40
  2. 2.60
  3. 11.40
  4. 12.60
Show the answer and explanation

Correct answer

D. 12.60

Principle or equation

pH = -log[H+]; for a strong base, pOH = -log[OH-] and pH + pOH = 14 at 25°C. Concentration is amount of substance divided by volume in litres.

Why this answer is correct

First calculate moles of NaOH: 0.40 g / 40 g/mol = 0.010 mol. Then concentration = 0.010 mol / 0.250 L = 0.040 mol/L. Since NaOH dissociates completely, [OH-] = 0.040 M. pOH = -log(0.040) = 1.40. Therefore pH = 14 - 1.40 = 12.60.

Example

For 0.020 mol NaOH in 500 mL, [OH-] = 0.040 M, pOH = 1.40, pH = 12.60.

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