How many moles of oxygen atoms are present in 22.0 g of carbon dioxide (CO2)? (Molar masses: C = 12.0 g/mol, O = 16.0 g/mol)
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Correct answer
B. 1.0 mol
Principle or equation
Moles of compound = mass / molar mass. Each mole of CO2 contains 2 moles of oxygen atoms.
Why this answer is correct
Molar mass of CO2 = 12.0 + 2(16.0) = 44.0 g/mol. Moles of CO2 = 22.0 g / 44.0 g/mol = 0.50 mol. Oxygen atoms = 0.50 mol × 2 = 1.0 mol.
Example
For 11.0 g CO2, moles = 0.25 mol, oxygen atoms = 0.50 mol.
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