How many moles of oxygen atoms are present in 88.0 g of carbon dioxide (CO2)? (Molar masses: C = 12.0 g/mol, O = 16.0 g/mol)
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Correct answer
C. 4.00 mol
Principle or equation
Molar mass of CO2 = 12.0 + 2(16.0) = 44.0 g/mol. Moles of CO2 = mass / molar mass. Each CO2 contains 2 moles of O atoms.
Why this answer is correct
Moles of CO2 = 88.0 g / 44.0 g/mol = 2.00 mol. Since each CO2 has 2 oxygen atoms, moles of O = 2.00 × 2 = 4.00 mol.
Example
For 22.0 g CO2, moles = 0.500 mol, O atoms = 1.00 mol.
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