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Reviewed CSCA Chemistry question · Easy

A solution is prepared by dissolving 0.0050 mol of a strong monoprotic acid HA in enough water to make 250 mL of solution. What is the pH of the resulting solution? Assume complete dissociation.

  1. 1.70
  2. 2.00
  3. 2.30
  4. 3.00
Show the answer and explanation

Correct answer

A. 1.70

Principle or equation

For a strong monoprotic acid, [H+] = concentration of the acid. pH = -log[H+]. Concentration = moles / volume in liters.

Why this answer is correct

Volume = 250 mL = 0.250 L. [HA] = 0.0050 mol / 0.250 L = 0.020 M. Since HA is a strong acid, [H+] = 0.020 M. pH = -log(0.020) = 1.70 (since log(0.02) = -1.699).

Example

If 0.010 mol HCl is dissolved in 500 mL, [H+] = 0.020 M, pH = 1.70.

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