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Reviewed CSCA Chemistry question · Standard

A student prepares a solution by dissolving 0.040 mol of a strong monoprotic acid HA in enough water to make 800 mL of solution. What is the pH of the resulting solution? Assume complete dissociation.

  1. 1.30
  2. 1.70
  3. 2.00
  4. 2.30
Show the answer and explanation

Correct answer

A. 1.30

Principle or equation

For a strong monoprotic acid, complete dissociation means [H+] equals the acid concentration. pH = -log[H+].

Why this answer is correct

Molarity = 0.040 mol / 0.800 L = 0.050 M. Since HA is strong, [H+] = 0.050 M. pH = -log(0.050) = 1.30.

Example

If 0.020 mol of HCl is dissolved in 500 mL, [H+] = 0.040 M, pH = 1.40.

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