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Reviewed CSCA Mathematics question · Hard

A line passes through the points (-3, 4) and (5, -2). What is the equation of the line in slope-intercept form?

  1. y = -3/4 x + 7/4
  2. y = -3/4 x - 7/4
  3. y = 3/4 x + 7/4
  4. y = -4/3 x + 0
Show the answer and explanation

Correct answer

A. y = -3/4 x + 7/4

Principle or equation

The slope m = (y2 - y1)/(x2 - x1). Then use point-slope form y - y1 = m(x - x1) and convert to slope-intercept y = mx + b.

Why this answer is correct

m = (-2 - 4)/(5 - (-3)) = -6/8 = -3/4. Using point (-3,4): y - 4 = -3/4 (x + 3) => y = -3/4 x - 9/4 + 4 => y = -3/4 x + 7/4.

Example

For points (1,2) and (3,6), slope = 2, equation y = 2x.

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