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Reviewed CSCA Physics question · Easy

In a sample of an ideal gas, the absolute temperature is doubled while the number of molecules and the volume are kept constant. What happens to the average translational kinetic energy of a single molecule?

  1. It becomes four times as large.
  2. It becomes twice as large.
  3. It becomes half as large.
  4. It remains unchanged.
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Correct answer

B. It becomes twice as large.

Principle or equation

The average translational kinetic energy of a molecule in an ideal gas is directly proportional to the absolute temperature: KE_avg = (3/2) k_B T.

Why this answer is correct

Since KE_avg is proportional to T, doubling the absolute temperature doubles the average translational kinetic energy.

Example

If T increases from 300 K to 600 K, KE_avg doubles.

This published item includes a stored explanation and passed the platform’s publication workflow. It is independent preparation material, not a claim of an official or recalled examination question.

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