In a sample of an ideal gas, the absolute temperature is doubled while the number of molecules and the volume are kept constant. What happens to the average translational kinetic energy of a single molecule?
Show the answer and explanation
Correct answer
B. It becomes twice as large.
Principle or equation
The average translational kinetic energy of a molecule in an ideal gas is directly proportional to the absolute temperature: KE_avg = (3/2) k_B T.
Why this answer is correct
Since KE_avg is proportional to T, doubling the absolute temperature doubles the average translational kinetic energy.
Example
If T increases from 300 K to 600 K, KE_avg doubles.
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