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Reviewed CSCA Physics question · Standard

A rigid container holds 1.6 mol of an ideal gas at a pressure of 2.4 × 10^5 Pa and a temperature of 360 K. The gas is heated at constant volume until its temperature reaches 540 K. What is the new pressure of the gas?

  1. 1.6 × 10^5 Pa
  2. 2.4 × 10^5 Pa
  3. 3.6 × 10^5 Pa
  4. 4.8 × 10^5 Pa
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Correct answer

C. 3.6 × 10^5 Pa

Principle or equation

For an ideal gas at constant volume, pressure is directly proportional to absolute temperature: P1/T1 = P2/T2.

Why this answer is correct

Using Gay-Lussac's law, P2 = P1 × (T2/T1) = 2.4 × 10^5 Pa × (540 K / 360 K) = 2.4 × 10^5 Pa × 1.5 = 3.6 × 10^5 Pa.

Example

If a gas at 1.0 × 10^5 Pa and 300 K is heated to 450 K at constant volume, new pressure = 1.0 × 10^5 × (450/300) = 1.5 × 10^5 Pa.

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