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Reviewed CSCA Physics question · Easy

一定质量的理想气体，初始状态压强为1.0×10⁵ Pa，体积为2.0 L，温度为300 K。若气体发生等温变化，体积变为4.0 L，求末态压强。

  1. 2.0×10⁴ Pa
  2. 5.0×10⁴ Pa
  3. 1.0×10⁵ Pa
  4. 2.0×10⁵ Pa
Show the answer and explanation

Correct answer

B. 5.0×10⁴ Pa

Principle or equation

玻意耳定律（等温变化）：p1V1 = p2V2。

Why this answer is correct

p2 = p1V1/V2 = (1.0×10⁵ × 2.0) / 4.0 = 5.0×10⁴ Pa。

Example

若初始压强2 atm，体积3 L，末体积6 L，则末压强1 atm。

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