Reviewed CSCA Physics question · Easy

A gas occupies 2.0 m^3 at a pressure of 1.0 x 10^5 Pa. If the temperature remains constant and the volume is reduced to 0.5 m^3, what is the new pressure?

2.5 x 10^4 Pa
4.0 x 10^5 Pa
2.0 x 10^5 Pa
1.0 x 10^5 Pa

Show the answer and explanation

Correct answer

B. 4.0 x 10^5 Pa

Principle or equation

Boyle's law for constant temperature: P1 V1 = P2 V2.

Why this answer is correct

P2 = P1 V1 / V2 = (1.0 x 10^5)(2.0) / 0.5 = 4.0 x 10^5 Pa.

Example

If V1=1 m^3, P1=100 kPa, V2=0.2 m^3, then P2=500 kPa.

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