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Reviewed CSCA Physics question · Easy

A rigid container holds 0.50 mol of an ideal gas at a pressure of 2.0 × 10^5 Pa and a temperature of 300 K. The gas is heated at constant volume until its temperature reaches 450 K. What is the new pressure of the gas?

  1. 1.3 × 10^5 Pa
  2. 2.0 × 10^5 Pa
  3. 3.0 × 10^5 Pa
  4. 4.5 × 10^5 Pa
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Correct answer

C. 3.0 × 10^5 Pa

Principle or equation

For an ideal gas at constant volume, P1/T1 = P2/T2 (Gay-Lussac's law).

Why this answer is correct

Using P1/T1 = P2/T2, we have P2 = P1 * T2 / T1 = 2.0×10^5 Pa * (450 K / 300 K) = 3.0×10^5 Pa.

Example

If a gas at 300 K and 1 atm is heated to 600 K at constant volume, its pressure becomes 2 atm.

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