Reviewed CSCA Physics question · Standard

A rigid container holds 3.0 mol of an ideal gas at a pressure of 2.0 × 10^5 Pa and a temperature of 300 K. The gas is heated at constant volume until its pressure becomes 3.0 × 10^5 Pa. What is the new temperature of the gas?

200 K
450 K
600 K
900 K

Show the answer and explanation

Correct answer

B. 450 K

Principle or equation

For an ideal gas at constant volume, pressure is directly proportional to absolute temperature: P1/T1 = P2/T2.

Why this answer is correct

Using P1/T1 = P2/T2, with P1 = 2.0×10^5 Pa, T1 = 300 K, P2 = 3.0×10^5 Pa, we get T2 = P2 * T1 / P1 = (3.0×10^5 * 300) / (2.0×10^5) = 450 K.

Example

If a gas at 300 K and 1 atm is heated at constant volume until pressure doubles, the new temperature is 600 K.

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